本地题面缓存已迁移,解析内容待补充。
OJ: noi_openjudge
题目 ID: ch0406-20
难度:未知
标签:python
日期: 2026-07-30 23:01
题意
完整题面见同目录的 problem.md。
思路
代码
Python代码
python
case_count = int(input())
for _ in range(case_count):
device_count = int(input())
devices = []
bandwidths = set()
for _ in range(device_count):
data = list(map(int, input().split()))
options = list(zip(data[1::2], data[2::2]))
devices.append(options)
bandwidths.update(bandwidth for bandwidth, _ in options)
best = 0.0
for bandwidth in bandwidths:
total_price = 0
for options in devices:
prices = [price for option_bandwidth, price in options if option_bandwidth >= bandwidth]
if not prices:
break
total_price += min(prices)
else:
best = max(best, bandwidth / total_price)
print(f"{best:.3f}")