题意与原解析均从本地 OpenJudge 缓存迁移。
OJ: noi_openjudge
题目 ID: ch0205-1253
难度:未知
标签:
日期: 2026-07-30 23:01
题意
完整题面见同目录的 problem.md。
思路
代码
cpp
#include <cstdio>
#include <cstring>
#include <queue>
using namespace std;
int fx[][3] = {
{0,0,1},
{0,1,0},
{0,0,-1},
{0,-1,0},
{1,0,0},
{-1,0,0}
};
char maze[35][35][35];
int vis[35][35][35];
int sx,sy,sz,tx,ty,tz;
int l,r,c;
struct sta {
int z,x,y,step;
};
void init(){
memset(maze,0,sizeof(maze));
memset(vis,0,sizeof(vis));
scanf("%d%d%d",&l,&r,&c);
int i,j,k;
for( i =1;i<=l;i++) {
for( j = 1;j<=r;j++){
scanf("%s",maze[i][j]+1);
for(k=1;k<=c;k++ ){
char &t = maze[i][j][k];
if( t == 'S')
sx = j,sy=k,sz=i;
else if( t == 'E')
tx = j,ty=k,tz=i;
}
}
}
}
bool in_map( int z,int x,int y) {
if(
z >= 1 && z <= l &&
x >=1 && x <= r &&
y >=1 && y <= c
)
return 1;
return 0;
}
int bfs(){
queue<sta> q;
q.push({sz,sx,sy,0});
vis[sz][sx][sy] = 1;
while( !q.empty()){
sta h = q.front();
q.pop();
int i;
for( i =0;i< 6 ;i++){
int nz = h.z+fx[i][0];
int nx = h.x+fx[i][1];
int ny = h.y+fx[i][2];
if( nz == tz && nx == tx && ny == ty)
return h.step +1;
if( in_map(nz,nx,ny) && !vis[nz][nx][ny] && maze[nz][nx][ny] == '.'){
q.push({nz,nx,ny,h.step+1});
vis[nz][nx][ny] = 1;
}
}
}
return -1;
}
int main(){
//freopen("c:\in","r",stdin);
while(1){
init();
if( l == 0 && r == 0 && c == 0) break;
int ans = bfs();
if( ans != -1)
printf("Escaped in %d minute(s).\n",ans);
else
printf("Trapped!\n");
}
return 0;
}